Solve this system of simultaneous equations:
3x+4y=19,2x- y=9
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Answer:
x = 5
y = 1
Step-by-step explanation:
3x + 4y =19 ...... (1)
2x - y =9.......(2)
multiplying equation2 by 4 , we get
4(2x - y )= 36
8x - 4y = 36.......(3)
adding eq. 1 and 3 , we get
11x=55
hence , x = 5
substituting value of x in eq 2 we get,
10 - y = 9
hence, y = 1
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