Question

Solve this;


$tan^{-1} (\dfrac{ 6x - 8x^{3}}{1 - 12x^{2}}) - tan^{-1} (\dfrac{4x}{1 - 4x^{2}}) = tan^{-1} 2x.$

Answer 1

Ignore my handwriting. hope it helps !

Answer 2

Answer:

$i \: think \: that \: u \: would \: not \: get \: my \: handwriting \\ but \: i \: think \: hope \: it \: helps \: you$