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1
Answer:
so, idk if it's correct but it's: = 0-2y²
Explanation:
bcs, 1) = x-y²-x-y²
=x-x-y²-y²
=0-2y²
Answered by
1
Explanation:
To find : (x-y)^2 -(x+y)^2
Solution:
(x-y)^2-(x+y)^2
Applying the formula we get,
=x^2+y^2-2xy -x^2-y^2-2xy
= -4xy
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