Math, asked by riyadas61, 8 months ago

solve this Theorem class 9​

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Answered by rozi23
4

Answer:

Ray OS stands on a line POQ.

therefore, <SOQ + <POS =180

Let the <POS be x

then ATQ,

x+<SOQ = 180-x

ROS = 1/2×<POS

=1/2×x =x/2

<SOT=1/2×<SOQ

= 1/2 ×(180°-x)

90°-x/2

x/2+90°-x/2

x/2 is canceled

So the answer is 90° hopefully ....

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