solve this Theorem class 9
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Ray OS stands on a line POQ.
therefore, <SOQ + <POS =180
Let the <POS be x
then ATQ,
x+<SOQ = 180-x
ROS = 1/2×<POS
=1/2×x =x/2
<SOT=1/2×<SOQ
= 1/2 ×(180°-x)
90°-x/2
x/2+90°-x/2
x/2 is canceled
So the answer is 90° hopefully ....
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