Solve this to be the brainliest(ignore the blue pen part)
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Hey dear friend
Construction=Join AP
To Prove=AP bisects angle BAC
Taking ∆APM and ∆APN
=>AP=AP. (Common side)
=>angle AMP=angle ANP. (Both are 90°)
=>PM = PN. (given)
=>So, by SAS cong. ∆APM=~∆APN
=> So angle MAP=angle NAP. (By CPCT)
So we can conclude that line AP bisects angle BAC because angle MAP is equal to angle NAP.
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
Construction=Join AP
To Prove=AP bisects angle BAC
Taking ∆APM and ∆APN
=>AP=AP. (Common side)
=>angle AMP=angle ANP. (Both are 90°)
=>PM = PN. (given)
=>So, by SAS cong. ∆APM=~∆APN
=> So angle MAP=angle NAP. (By CPCT)
So we can conclude that line AP bisects angle BAC because angle MAP is equal to angle NAP.
Be PERFECTIONIST
hope it helps you mark me as brainliest and follow me
conjureroman:
mark me as brainliest and follow me
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