Math, asked by jaiswalayush975, 9 months ago

Solve this trigonometrical question please​

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Answers

Answered by rohitkumar5031
1

Answer:

Answer is in the attachment

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Answered by ITzBrainlyGuy
0

Answer:

Taking LHS from the question

Used formulas:

cos²θ = 1 - sin²θ

→ cosθ/sinθ = cotθ

 \frac{1 +  \cos( \theta) -  { \sin( \theta) }^{2}  }{ \sin( \theta) (1 +  \cos( \theta)) }

using first formula

 =  \frac{1 +  \cos( \theta)  - (1 -  { \cos( \theta) )}^{2} }{ \sin(   \theta ) (1 +  \cos( \theta) )}

   =  \dfrac{1 +  \cos( \theta )  - 1 +  { \cos( \theta) }^{2} }{ \sin( \theta)  +  \sin( \theta)  \cos( \theta) }  \\  \\  =  \dfrac{ \cos( \theta)(1 +  \cos( \theta)  )}{ \sin( \theta) (1 +  \cos( \theta)) }  \\  \\  =  \frac{ \cos( \theta) }{ \sin( \theta) }

Using second formula

= cotθ

Concepts used:

trigonometric ratios

→ trigonometric identities

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