Math, asked by karthiknayak11, 1 year ago

solve this

trigonometry problem!!​

Attachments:

Answers

Answered by abiviji502
2

L.H.S. = sinA - cosA +1/sinA+cosA-1

= sinA - ( cosA -1)/ sinA +( cosA -1)

multiply numerator & denominator by numerator

= { sinA^2 - (cosA-1)^2/ [ sinA + cosA-1]^2

= [sin^2A-cos^2A+2cosA-1]/sin^2A+cos^2A+1+...

={ 2cosA - cos^2A-(1-sin^2A)}/ {2+ 2sinAcosA-2sinA-2cosA}

= 2cosA( 1- cosA)/ {2( 1- cosA) - 2sinA( 1- cosA) }

=2cosA/2 (1- sinA)

= 1/(1- sinA)/cosA

= 1/1/cosA - sinA/cosA

= 1/secA - tanA

= R.H.S

i think answer will be use full

Similar questions