Question

solve this trigonometry question

Answer 1

Now, From Eqⁿ i, ii and iii, we get:
$\sin( \alpha + \beta ) = \frac{5}{13} \times \frac{3}{5} + \frac{4}{5} \times \frac{12}{13} \\ = > \sin( \alpha + \beta ) = \frac{63}{65}$