solve this trigonometry question
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sin^2 x + cos^2 x = 1
Square both sides
=> sin^4 x + cos^4 x + 2 sin^2 x cos^2 x = 1
=> 1/2 +2 sin^2 x cos^2 x = 1
=> 2 sin^2 x cos^2 x = 1/2
=> sin^2 x cos^2 x = 1/4
=> sin x cos x = 1/2
Square both sides
=> sin^4 x + cos^4 x + 2 sin^2 x cos^2 x = 1
=> 1/2 +2 sin^2 x cos^2 x = 1
=> 2 sin^2 x cos^2 x = 1/2
=> sin^2 x cos^2 x = 1/4
=> sin x cos x = 1/2
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Solution:
★ we know that sin⁴θ + cos⁴θ = 1 - 2 sin²θ cos²θ
Given, sin⁴θ + cos⁴θ = ½
→ 1 - 2 sin²θ cos²θ = ½
½ = 2 sin²θ cos²θ → (sinθ cosθ)²
→ sinθ cosθ = ± ½
Hope it's help ful to you
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