Question

solve this urgent
1.(x + 1) (3 - x)
2.(5 - x) (X + 8)
find by inspection the efficient of X in the following expansion​

Answer 1

Answer:

(1−x−x2+x3)6=[(1−x)−x2(1−x)]6

=(1−x)6(1−x2)6

=(1−6x+15x2−20x3+15x4−6x5+x6)

×(1−6x2+15x4−20x6+15x8−6x10+x12)

Coefficient of x7=(−6)(−20)+(−20)(15)+(−6)(−6)=−144.

Step-by-step explanation:

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