Solve this using elimination method : x/2+2y/3=-1 ; x-y/3=3
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x/2+2y/3=-1 1)
x-y/3=3 2)
multiplying 1)by 2
x+4y/3=-1 3)
x-y/3=3
- + -
subtracting
4y+y/3=-4
5y/3=-4
y=-4*3/5
y=-12/5
sustituting value of y in 1)
x/2+2(-12/5)/3=-1
x/2+2(-4/5)=-1
x/2-8/5=-1
x/2=-1+8/5
x/2=-5+8/5
x/2=3/5
x=6/5
x-y/3=3 2)
multiplying 1)by 2
x+4y/3=-1 3)
x-y/3=3
- + -
subtracting
4y+y/3=-4
5y/3=-4
y=-4*3/5
y=-12/5
sustituting value of y in 1)
x/2+2(-12/5)/3=-1
x/2+2(-4/5)=-1
x/2-8/5=-1
x/2=-1+8/5
x/2=-5+8/5
x/2=3/5
x=6/5
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