Question

solve this using factoring 2y²+8y-10=0​

Answer 1

Factorise 2y² + 8y - 10

While factorising, we need to find the numbers which when multiplied gives 20 and which when added or subtracted gives 8.

The required 2 numbers are 2, -10

Now, split the middle term

2y² + 2y - 10y - 10 = 0

⇒2y(y + 1) - 10(y + 1)

⇒(2y - 10)(y + 1)

Therefore, the factors are:

1. (2y - 10)
2. (y + 1)

Answer 2

Answer:

You Have already Explained and Answered the Question