Question

solve this with the clear steps

Answer 1

radius of circle=6 cm
angle subtended at centre=60°
area of minor sector=3.14×6×6×60÷360=18.84 cm ²
area circle=3.14×6²=113.04 cm ²
area of triangle=√3/2×a²=1.73×12²÷2=124.56 cm ²
area of shaded region=218.76 cm ²

Answer 2

Hi ,

1 ) radius of the circle ( r ) = 6 cm

2 ) OLD sector angle ( x° ) = 60°

3 ) side of the equilateral = a = 12cm

4 ) area of the required region

= Area of the circle + area equilateral

Triangle - 2 × area of the sector

= π r² + √3/4 × a² - 2 × ( x/360) × π r²

= 3.14 × 6² + 1.73/4 × 12² - 2 × ( 60/360 ) × 3.14 × 6²

= 3.14 × 36 + 1.73 × 36 - 2 × 3.14 × 6

= 24× 3.14 + 1.73 × 36

= 75.36 + 62.28

= 137.64 sq cm

I hope this helps you.

:)