Question

solve this:. (√x)^-2/3 √y^4÷√xy-1/3​

Answer 1

Answer:

$\frac{ {( \sqrt{x} )}^{ \frac{ - 2}{3} } \sqrt{ {y}^{4} } }{ \sqrt{xy} - \frac{1}{3} } \\ \\ = \frac{ \frac{1}{ { (\sqrt{x}) }^{ \frac{2}{3} } }( {y}^{2}) }{ \sqrt{xy} - \frac{ 1}{3} } \\ \\ = \frac{ \frac{1 }{ \sqrt[3]{ \sqrt{ {x}^{2} } } } ( {y}^{2} )}{ \sqrt{xy} - \frac{1}{3} } \\ \\ = \frac{ \sqrt[ 3]{x} ( {y}^{2}) } { \sqrt{xy} - \frac{1}{3} } \\ \\ = \frac{ {y}^{2} \sqrt[ 3]{x} } { \sqrt{xy} - \frac{1}{ 3} }$

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