Question

solve thisssssss________!!!!!!!!!!


separately ​

Answer 1

Given inner radius of hemispherical tank (r) = 1m  

Thikness of iron sheet = 1 cm = 0.01m  (since 100cm = 1m)

Now outer radius of hemispherical tank(R) = 1+0.01 = 1.01 m

Now volume of hemispherical tank = (2/3) *pie*(R3 - r3 )

                                                = (2/3) *3.14*(1.013 - 13 )  

                                                = (2/3) *3.14*(1.030301 - 1)

                                                = (2/3) *3.14*0.030301

                                                = (6.28*0.030301)/3

                                                = 0.19029028/3

                                                = 0.06343 m3

So volume of the iron used to make the tank = 0.06343 m3

The answer to second part

Surface Area of tank = 5a2      (Area of 5 faces only)

Area of one square tile = lb

= 25 cross times25 cm2

Cost of 180 tiles =480 over 12 cross times 180  

= Rs. 7200