solve tjis
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SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT
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Answer:
we know that tan30=1/√3
=> 2tan30°/1-tan² 30°
=> 2(1/√3)/1-((1/√3)^2)
=> 2(1/√3)/1-(1/3)
=> 2(1/√3)/(2/3)
=> √3
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