Question

Factorise 2√2 x^3+8 y^3-27 z^3+18√2 xyz

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

we can write 2√2x³=(√2x)³

8y³=(2y)³

-27z³=(-3z)³

let a = √2x

b=2y

c=-3z

Step-by-step explanation:

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

putting values of a,b and c

=(√2x+2y-3z)((√2x)²+(2y)²+(-3z)²-(√2x)(2y)-(2y)(-3z)-(-3z)(√2x)

=(√2x+2y-3z)(2x²+4y²+9z²-2√2xy-6yz+6xz)

=(√2x)(2x²+4y²+9z²-2√2xy-6yz+6xz)+2y(2x²+4y²+9z²-2√2xy-6yz+6xz)-3z(2x²+4y²+9z²-2√2xy-6yz+6xz)

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