Question

Solve to find value of a,b,c from these equation: a+b+c=1
2a-3b+2c = 3
2a+3c = 2

Answer 1

Answer:

a = 8/5, b = -1/5, c = -2/5

Step-by-step explanation:

a+b+c=1

=> b = 1-a-c ---(1)

2a-3b+2c = 3

=> 2a -3(1-a-c)+2c = 3 [putting b from (1)]

=> 2a -3 + 3a + 3c + 2c = 3

=> 5a + 5c = 3+3 = 6 ---(2)

2a+3c = 2 ---(3)

(2)×2 : 10a+10c = 12

(3)×5 : 10a+15c = 10

- - -

--------------------------------

-5c = 2

=> c = -2/5

=> 2a+3c = 2 (3)

=> 2a+3(-2/5) = 2

=> 2a = 2+6/5 = 16/5

=> a = 8/5

=> b = 1-a-c (1)

=> b = 1-8/5+2/5

=> b = -1/5