solve to: x+1√x^2+5x+6
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Step-by-step explanation:
x+1/√x^2+5x+6
x+1/x+5x+6. [(√x)^2=x because √x is also can be written as x^1/2and exponent is multiplied with power which is already given i.e,x^1/2×2 so power will be 1 . x^1 i.e, only x so √x^2 = x]
then ,we take l.c.m of denominator x so equation will be x^2+1+5x^2+6x
after adding it will be 6x^2+6x+1
then we apply shridharacharya rule which is (-b+-√b^2-4ac)/2a
(-6+-√6^2-4×6×1)/2×6
[after putting the value of a,b,and c]
then,after calculate we will get
(-6+-√12)/12 = -6/12+-√12/12
-1/2+-√12/12. its final ans
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