Question

solve trigonometry 2uwiiwowowqoo

Answer 1

your answer is :-


see the attachment

Answer 2

$\bold{\boxed{HEY!!!}}$



HERE IS YOUR ANSWER



$\frac{1}{1 - \sin( \alpha ) } + \frac{1}{1 + \sin( \alpha ) } = 2 { \sec}^{2} \alpha \\ \\ \\ on \: lhs \: \\ \\ \\ \frac{1 + \sin( \alpha ) + 1 - \sin( \alpha ) }{(1 - \sin ( \alpha ))(1 - \sin( \alpha ) } \\ \\ \\ = \frac{2}{1 - { \sin }^{2} \alpha } \\ \\ \\ = \frac{2}{ { \cos }^{2} \alpha } \\ \\ \\ = 2. \frac{1}{ { \cos }^{2} \alpha } \\ \\ \\ = 2{ \sec }^{2} \alpha \\ \\ \\ = rhs \\ \\ \\ hence \: proved$