solve upto 2 decimal places x2-5x-5=0
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Answer:
The value of x up to 2 decimal places = 6.52 or, - 1.52
Step-by-step explanation:
The given quadratic equation:
x^2-5x-10=0x
2
−5x−10=0
To find, the value of x up to 2 decimal places = ?
Here, a = 1, b = - 5 and c = - 10
∴ Discriminant,
D=b^{2}-4acD=b
2
−4ac
=(-5)^{2}-4(1)(-10)=(−5)
2
−4(1)(−10)
= 25 + 40
= 65 > 0, the roots are real and unequal.
x=\dfrac{-b±\sqrt{D}}{2a}x=
2a
−b±
D
∴ x=\dfrac{-(-5)±\sqrt{65}}{2(1)}x=
2(1)
−(−5)±
65
x=\dfrac{5±8.06}{2}x=
2
5±8.06
x=\dfrac{5+8.06}{2}
2
5+8.06
or, \dfrac{5-8.06}{2}
2
5−8.06
= 6.52 or, - 1.52
Hence, the value of x up to 2 decimal places = 6.52 or, - 1.52.
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