Math, asked by meenaumesh029, 8 months ago

solve upto 2 decimal places x2-5x-5=0​

Answers

Answered by unigashotel
1

Answer:

The value of x up to 2 decimal places = 6.52 or, - 1.52

Step-by-step explanation:

The given quadratic equation:

x^2-5x-10=0x

2

−5x−10=0

To find, the value of x up to 2 decimal places = ?

Here, a = 1, b = - 5 and c = - 10

∴ Discriminant,

D=b^{2}-4acD=b

2

−4ac

=(-5)^{2}-4(1)(-10)=(−5)

2

−4(1)(−10)

= 25 + 40

= 65 > 0, the roots are real and unequal.

x=\dfrac{-b±\sqrt{D}}{2a}x=

2a

−b±

D

∴ x=\dfrac{-(-5)±\sqrt{65}}{2(1)}x=

2(1)

−(−5)±

65

x=\dfrac{5±8.06}{2}x=

2

5±8.06

x=\dfrac{5+8.06}{2}

2

5+8.06

or, \dfrac{5-8.06}{2}

2

5−8.06

= 6.52 or, - 1.52

Hence, the value of x up to 2 decimal places = 6.52 or, - 1.52.

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