Question

Solve using Algebraic identity:-
49p²– 70pq + 25q² where p =2/3 and q = −1/5

Answer 1

Answer:

(7p-5q)²

Step-by-step explanation:

49p²-70Pa+25q²

=(7p)²-2(7p)(5q)+(5q)²

[Using identity (a-b)²=a²-2ab+b²]

=(7p-5q)²

I think there is no use of values of "p" and "q".

Answer 2

$49 {p}^{2} - 70pq + {25q}^{2}$

$= {(7p)}^{2} - (2)(7p)(5q) + {(5q)}^{2}$

$= {(7p - 5q)}^{2}$

$= {(7(\frac{2}{3}) - 5(\frac{ - 1}{5}))}^{2}$

$= {(\frac{14}{3} + \frac{5}{5})}^{2}$

$= {( \frac{70 + 15}{15})}^{2}$

$= { (\frac{85}{15}) }^{2}$

$= {( \frac{17}{3} )}^{2}$

$= \frac{ {17}^{2} }{ {3}^{2} }$

$= \frac{289}{9}$

Hope this helps.

Thanks.