Question

Solve using BODMAS


[15+6{8-7(32-21)+(5+9)}]÷3(6+5)


Write answer through decimals if needed​

Answer 1

$\huge\bf\pink{\mid{\overline{\underline{Answer :- }}}\mid}$

We have given equation,

[15+6{8-7(32-21)+(5+9)}]÷3(6+5)

B ➝ Bracket

O ➝ Of

D ➝ Division

M ➝ Multiplication

A ➝ Addition

S ➝ Subtraction

➝ [15+6{8-7(32-21)+(5+9)}]÷3(6+5)

• First solve small bracket

➝ [15+6{8-7(224 - 147)+(14)}]÷3(11)

➝ [15+6{8-7(77)+(14)}]÷3(11)

➝ [15+6{8-7(91)}]÷3(11)

➝ [15+6{1(91)}]÷3(11)

➝ [15+6{1(91)}]÷3(11)

➝ 15 + 546 ÷ 33

➝ 561 ÷ 33

➝ 17

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Answer 2

$\Huge \purple {\mathbb {ANSWER:}}$$\footnotesize \pink {\tt {Given: \: [15+6{8-7(32-21)+(5+9)}]÷3(6+5)}}$$\huge \purple {\mathbb {EXPLANATION:}}$$\huge \red {\sf {B \: = \: Brackets}}$$\huge \green {\sf {O \: = \: Of}}$$\huge \orange {\sf {D \: = \: Division}}$$\huge \blue {\sf {M \: = \: Multiplication}}$ $\huge \purple {\sf {A \: = \: Addition}}$$\huge \pink {\sf {S \: = \: Subtraction}}$

$\normalsize \orange {\tt {[15+6{8-7(32-21)+(5+9)}]÷3(6+5)}}$$\normalsize \orange {\tt {= ~ [15+6{8-7(11)+(14)}]÷3(11)}}$ $\normalsize \orange {\tt {= ~ [15 + 6{8-7(91)}]÷3(11)}}$$\normalsize \orange {\tt {=~ [15 + 6{91}]÷3(11)}}$$\normalsize \orange {\tt {=~ 15+546÷33}}$$\normalsize \orange {\tt {=~ 561÷33}}$$\normalsize \orange {\tt {=~17}}$