Solve using completing the Square method.
x^2+8x-48=0
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Answer:
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x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
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x^{2}+8x-48=0
x2+8x−48=0
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a={\color{#c92786}{1}}
a=1
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8
b={\color{#e8710a}{8}}
b=8
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8
c={\color{#129eaf}{-48}}
c=−48
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