Question

solve using cross multiplication 2x+3y-17=0 and 3x-zy-6=0​sss​

Answer 1

Answer:

x=4 and y=3

Step-by-step explanation:

Given : Equation 2x+3y=172x+3y=17 and  3x-2y=63x−2y=6

To find : Solve the system of equation by method of cross multiplication?

Solution :

Let Coefficient of x - A

Coefficient of y - B

Constant term - C

Method of cross multiplication is

     x                                    y                                       -1

B       C                      C              A                        A                B

3        -17                    -17             2                       2                  3

-2        -6                    -6              3                       3                  -2

Cross multiply,

     x                                    y                                       -1

 (-18-(34))                       (-51-(-12))                             (-4-9)

   (-52)                               (39)                                  (-13)

Comparing x , i.e. \frac{x}{-52}=\frac{1}{13}−52x=131

x=\frac{-52}{13}x=13−52

x=4x=4

Comparing y , i.e. \frac{y}{39}=\frac{1}{13}39y=131

y=\frac{39}{13}y=1339

y=3y=3

Therefore, The value of x is 4 and the value of y is 3.

Answer 2

Answer:

To factor a trinomial in the form x2 + bx + c, find two integers, r and s, whose product is c and whose sum is b. Rewrite the trinomial as x2 + rx + sx + c and then use grouping and the distributive property to factor the polynomial. The resulting factors will be (x + r) and (x + s).