Question

Solve using distributive law(a+2)(2a+3)(a-1)

Answer 1

Answer:

Solve using distributive law(a+2)(2a+3)(a-1)

Answer 2

Answer:

$(a + 2)(2a + 3)(a - 1) \\ \\ = 2 {a}^{2} + 3a + 4a + 6(a - 1) \\ \\ = 2 {a}^{2} + 7a + 6(a - 1) \\ \\ = 2 {a}^{3} - 2 {a}^{2} + 7 {a}^{2} - 7a + 6a - 6 \\ \\ = 2 {a}^{3} + 5 {a}^{2} + 6a - 6$

hope this much helps uh ❣️