Question

Solve using formula:- b² - 4 ac

Answer 1

Here is the solution
Equation = y^2+1/3y-2=0
formula=b^2-4ac
=(1/3)^2-4*1*-2
=1/9+8
=73/9
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Answer 2

D=
${b}^{2} - 4ac$
therefore,her
D=
$( {1 }^{2} \div {3}^{2} ) - 4 \times 5 \times ( - 2)$
this becomes 1/9+40=361/9
now y=
$(- b + - \sqrt{d} ) \div 2a$
so here y=
$(- (1 \div 3) + -( \sqrt{361} \div 3)) \div 10$

so you two values of y one with the sign between b and d as + and one with the sign in between b and d as -.