Math, asked by vic99, 1 year ago

solve using heron's formula

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Answered by Equestriadash
4

Let a be 60m, b be 100m and c be 140m

Heron's formula: √s(s - a)(s - b)(s - c)

a + b + c = 60 + 100 + 140 = 300m

S = a + b + c/2 = 300/2 = 150m

s - a = 150 - 60 = 90m

s - b = 150 - 100 = 50m

s - c = 150 - 140 = 10m

√s(s - a)(s - b)(s - c)

√150*90*50*10

= √3*5*10*3*3*10*5*10*10

= 3*5*10*10√3

= 1500√3m^2


Hope it helps :)



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Answered by Anonymous
21
Hey Buddy ,
As we, know Heron's Formula :-
 \sqrt{s(s - a) \: (s - b) \: (s - c) }
where s =
sum \: of \: all \: side \div2
then \: giving \: sides \: are \:

60m, 100m& 140m

so , first of all find s
S = 60 +100 +140 ÷ 2
S = 300 ÷ 2
S = 150
put all in formula
√s(150-60)(150-100)(150-140)
√150(90)(50)(10)
√3×5×10(9×10)(5×10)(10)
5×100×3√3
15000√3


Hope it may helped u...

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