Math, asked by malli3205, 9 months ago

Solve using identity 27x^3-8y^3

Answers

Answered by Anonymous
2

 =  27 {x}^{3}  - 8 {y}^{3} \\  = (3x - 2y)(9 {x}^{2}  + 6xy + 4 {y}^{2} )

Answered by madhulathahoney2026
4

Answer:

27x³+8y³

(3x) ³+(2y) ³

using the formula a³+b³=(a+b)(a²-ab+b²)

we get

(3x+2y)[(3x) ²-(3x) (2y) ]+(2y)²

(3x+2y)(9x²-6xy+4y²)

plz mark it as the brainliest answer

Similar questions