Math, asked by wwwkomalpreet6478, 1 month ago

solve using identity (2a-3b)³​

Answers

Answered by aratisikdar7
2

Answer:

(2a−3b) ^3

=(2a)^3 +(−3b)^3 +3(2a)(−3b)(2a−3b)

=(8a)^3−(27b )^3−18ab(2a−3b)

=(8a)^3−(27b)^3 −36a^2b+54ab^2.

Answered by sahniraj12343
0

may it help uh

use formula...

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