solve using quadractic equations:1/x-1x-2=3
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Secondary School Math 5 points
Solve for X, using quadratic formula 1/x-1/x-2=3, x not equal to 0,2
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mysticd
mysticd Genius
Hi ,
1/x - 1/( x - 2 ) = 3
[ ( x - 2 - x ) ]/[ x ( x - 2 ) ] = 3
=> -2 = 3x( x - 2 )
=> 3x² - 2x = -2
divide each term with 3 , we get
x² - 2x/3 = -2/3
x² - 2 × x ×1/3 = -2/3
x² - 2 × x × 1/3 + ( 1/3 )² = ( 1/3 )² - 2/3
( x - 1/3 )² = 1/9 - 2/3
( x - 1/3 )² = ( 1 - 6 )/9
x - 1/3 = ± √(-5 ) /3
x = 1/3 ± √5 i /3
x = ( 1 ± √5i )/3
I hope this helps you.
: )
Answer:
Step-by-step explanation:
[1/x]-1x-2=3
[1-x²-2x]/x=3
1-x²-2x=3x
1-x²-2x-3x=0
1-x²-5x=0
x²+5x-1=0
we get imaginary roots
by using the formula we can find
I will give the formula then please you do yourself
x=[-b±√(b²-4ac)]/2a
here b=coefficient of x
a=coefficient of x²
c=constant