Question

Solve using substitution method
2p=14-x (eq1)
12p=14-x (eq2)

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Answer 1

Step-by-step explanation:

p=14-x/2.... (1)

12p=14_x ... (2)

putting the value of p from equation 1 to 2

12 (14_x)/2=14_x

168_12x/2=14_x

168_12x=28_2x

168_28=_2x+12x

140=10x

x=140/10

x=10

putting x=14in equation 1

p=14_14/2

p=0/2

p=0

hence p=0andx=14