Question

solve with factorisation

$x2 - 17x + 60 = 0$

Answer 1

Given the equation - 
x² - 17x + 60 = 0
⇒x² - 12x - 5x + 60 = 0 
⇒x(x - 12) - 5(x - 12) = 0
⇒(x-12)(x-5) = 0
∴ (x-12) = 0  and (x - 5) = 0
or, x is either equal to 12 or 5.

Hope this answer helps you and mark it as the brainliest answer. 

Answer 2

Answer:

$x= 12$ or $x=15$

Step-by-step explanation:

Given equation:

$x^{2} -17x+60=0$
Now, we will factorise 60, such that the sum of the products somehow gives 17, in order to split it,
60= 2×3×2×5

We can write 17 as 12+5
Thus, $17x$ can be written as $12x+5x$

⇒ $x^{2}-(12x+5x)+60=0$
⇒ $x^{2}-12x-5x+60=0$
⇒ $x(x-12)-5(x-12)=0$
∴$x= 12$ or $x=15$