Question

Solve with steps.....

Answer 1

HEY MATE HERE IS YOUR ANSWER

${x}^{2} + x - 2 \\ {x}^{2} - x + 2x - 2 \\ x(x - 1) + 2(x - 1) \\ (x + 2)(x -1)$
Hence the two zeros are -2,1
$\alpha = - 2 \\ \beta = 1$
$\frac{1}{ \alpha } - \frac{1}{ \beta } \\ \frac{1}{ - 2} - \frac{1}{1} \\ \\ \frac{ - 3}{2}$
HOPE IT HELPS YOU

FOLLOW ME FOR ANY OTHER QUESTIONS

Answer 2

it's your answer...

\begin{lgathered}{x}^{2} + x - 2 \\ {x}^{2} - x + 2x - 2 \\ x(x - 1) + 2(x - 1) \\ (x + 2)(x -1) \\\end{lgathered}

x

2

+x−2

x

2

−x+2x−2

x(x−1)+2(x−1)

(x+2)(x−1)

Hence the two zeros are -2,1

\begin{lgathered}\alpha = - 2 \\ \beta = 1\end{lgathered}

α=−2

β=1

\begin{lgathered}\frac{1}{ \alpha } - \frac{1}{ \beta } \\ \frac{1}{ - 2} - \frac{1}{1} \\ \\ \frac{ - 3}{2}\end{lgathered}

α

1

−

β

1

−2

1

−

1

1

2

−3

plz mark me brilliant......