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In triangle ADC,
⇒ b=60
o
+70
o
⇒ b = 130
o
Now, in triangle ABD,
⇒ a+b+30
o
= 180
o
⇒ a = 180
o
−30
o
- 130
o
⇒ a = 20
o
Also,
∠ADC=∠BAD+∠ABD .... Exterior angle property
⇒ c=30
o
+a
⇒ c=30
o
+20
o
⇒ c=50
o
Therefore,
a=20
o
, b=130
0
, c=50
o
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