solve without calculating the cubes and state the property to use. -
i- (-12)³+(7)³+(5)³ ii- (28)³+(-15)³+(13)³
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Answer:
i)-1260 ii)16380
Step-by-step explanation:
Let's move to some basic concepts of expansion,
we have learnt that if a+b+c=0, then a^3+b^3+c^3=3abc.
in (i),
let a=-12,
b=7,
c=5
a+b+c =0 in this case,
and hence, (-12)^3+(7)^3+(5)^3=3(-12)(7)(5)=-1260.
in (ii),
let a=28
b=-15,
c=-13
a+b+c=0 in this case,
and hence, (28)^3+(-15)^3+(-13)^3=3(-13)(-15)(28)=16,380.
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