Question

solve x^2+16x+55 by factorising​

Answer 1

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solve x^2+16x+55 by factorising.

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The first term is, $<font color= red>$x2 $<font color= black>$ its coefficient is 1 .

The middle term is, $<font color= red>$-16x $<font color= black>$its coefficient is -16 .

The last term, "the constant", is $<font color= red>$+55

$<font color= black>$

Step-1 : Multiply the coefficient of the first term by the constant 1 • 55 = 55

Step-2 : Find two factors of 55 whose sum equals the coefficient of the middle term, which is $<font color= red>$ -16 .

$<font color= black>$

-55 + -1 = -56

-11 + -5 = -16 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -11 and -5

x2 - 11x - 5x - 55

Step-4 : Add up the first 2 terms, pulling out like factors :

$<font color= red>$ x • (x-11)

$<font color= black>$ Add up the last 2 terms, pulling out common factors :

$<font color= red>$ 5 • (x-11)$<font color= black>$

Step-5 : Add up the four terms of step 4 :

$<font color= red>$ (x-5) • (x-11)

$<font color= black>$ Which is the desired factorization

Equation at the end of step 1 :

(x - 5) • (x - 11) = $<font color= blue>$0

Answer 2

Answer:

hope it helps you (:

Step-by-step explanation: