Question

solve |x^2+3x|>2-x^2​

Answer 1

Answer:

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x = -1.

Step-by-step explanation:

$| {x}^{2} + 3x | > 2 - {x}^{2} \\ {x}^{2} + 3x \: > 2 - {x}^{2} \\ 2 {x}^{2} + 3x - 2 > 0 \\ 2 {x}^{2} + 4x - x - 2 > 0 \\ 2x(x + 2) - 2(x + 2) > 0 \\ (2x - 2)(x + 2) > \\ x \: lies \: between \\ - 2 < x < 1$

then x= -1,0

x is suitable for -1 bcoz if u substitute x = -1 then

LHS = RHS

-2 = -2