Question

solve [x]^2 -7[ x]+12=0​

Answer 1

Answer:

Step-by-step explanation:

x²-3x-4x+12

x(x-3)-4(x-3)

(X-3)(x-4)

Answer 2

Answer:

x² - 7x + 12 = 0

x² - 3x - 4x + 12 = 0

x ( x - 3 ) - 4 ( x - 3 ) = 0

( x - 4 ) ( x - 3 ) = 0

x = 4 or 3