Solve : x 2 + 8x + 4 = 0 by completing the square method.
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Answered by
34
x²+8x+4=0
(x²+2*x*4 +4²)-4²+4=0
(x+4)²-16+4=0
(x+4)²-12=0
(x+4)²=12
(x+4)=plus or minus √12
x+4 = plus or minus 2√3
therefore
x=-4+2√3 or x= -4-2√3
(x²+2*x*4 +4²)-4²+4=0
(x+4)²-16+4=0
(x+4)²-12=0
(x+4)²=12
(x+4)=plus or minus √12
x+4 = plus or minus 2√3
therefore
x=-4+2√3 or x= -4-2√3
Answered by
7
Answer:
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Step-by-step explanation:
x²+8x+4=0
(x²+2*x*4 +4²)-4²+4=0
(x+4)²-16+4=0
(x+4)²-12=0
(x+4)²=12
(x+4)=plus or minus √12
x+4 = plus or minus 2√3
therefore
x=-4+2√3 or x= -4-2√3
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