Solve: x^2 - | x | - 12 < 0
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Solution!!
x² - | x | - 12 < 0
Separating the inequality into 2 possible cases.
x² - x - 12 < 0 , x ≥ 0
x² - (-x) - 12 < 0 , x < 0
Solving for x.
x² + 3x - 4x - 12 < 0 , x ≥ 0
x² + x - 12 < 0 , x < 0
x(x + 3) - 4(x + 3) < 0
x² + 4x - 3x - 12 < 0
(x + 3)(x - 4) < 0
x(x + 4) - 3(x + 4) < 0
x < -3 or x < 4
(x + 4)(x - 3) < 0
x < -3 or x < 4
x < -4 or x < 3
x ∈ (-3 , 4) , x ≥ 0
x ∈ (-4 , 3) , x < 0
Finding the intersection.
x ∈ (0 , 4) , x ≥ 0
x ∈ (-4 , 0) , x < 0
Finding the union.
x ∈ (-4 , 4)
Intersection of two sets contain only the elements that are in both the sets.
Union of two sets contains all the elements of one set or both the sets..
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