solve: x^2+x-(a+2)(a+1)
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Answered by
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Answer:
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x^{2}+x{\color{#c92786}{-a(a+1)}}-2(a+1)
x2+x−a(a+1)−2(a+1)
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Answered by
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Answer:
Answer:
x =(a+1) Or x = -(a+2) are two roots of given quadratic equation.
Step-by-step explanation:
Given quadratic equation :
x²+x-(a+1)(a+2)=0
Splitting the middle term, we get
=> x²(a+1)x+(a+2)x-(a+1)(a+2)=0
=> x[x-(a+1)]+(a+2)[x-(a+1)]=0
=> [x-(a+1)][x+(a+2)]=0
=> x-(a+1)=0 Or x+(a+2)=0
=> x = (a+1) Orx = -(a+2)
Therefore,
x =(a+1) Or x = -(a+2) are two roots of given quadratic equation.
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