solve: x^2+x(r-q)-(p-r)(p-q)=0
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Answer:
x = p-r Or x = q-p
Step-by-step explanation:
x²-(p-r)x+(p-q)x-(p-r)(p-q) =0
=> x[x-(p-r)]+(p-q)[x-(p-r)]=0
=> [x-(p-r)][x+(p-q)]=0
=> x-(p-r)=0 Or x+(p-q)=0
=> x = p-r Or x = q-p
Therefore,
x = p-r Or x = q-p
•••♪
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