Solve: x + 2y = 5 and 2y + 3x = 3 by substitution method
Answers
Answered by
0
let X+2y=5 be the first equation and 2y+3x=3 be the second equation
now from first equation X=5-2y and let this be the third equation
now substitute equation 3 in equation 2
therefore,y = 3 now substitute this value in equation 2 , therefore the value of X= -1
now from first equation X=5-2y and let this be the third equation
now substitute equation 3 in equation 2
therefore,y = 3 now substitute this value in equation 2 , therefore the value of X= -1
Answered by
2
THANKS FOR THE QUESTION !
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
GIVEN :
=> X + 2Y = 5 ..................1
=> 3X + 2Y = 3 ................2
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
TAKE EQN. 1 AND MAKE IT READY TO SUBSTITUTING ......
=> X + 2Y = 5
=> X = 5 - 2Y .....................3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT EQN . 3 IN EQN. 2
=> 3 ( 5 - 2Y ) + 2Y = 3
=> 15 - 6Y + 2Y = 3
=> -4Y = 3 - 15
=> -4Y = -12
=> Y = -12 / -4
=> Y = 3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT Y = 3 IN EQN . 1
=> X + 2Y = 5
=> X + 2*3 = 5
=> X + 6 = 5
=> X = 5-6
=> X = -1
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
HOPE IT WILL HELP U.....
THANKS AGAIN.......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
GIVEN :
=> X + 2Y = 5 ..................1
=> 3X + 2Y = 3 ................2
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
TAKE EQN. 1 AND MAKE IT READY TO SUBSTITUTING ......
=> X + 2Y = 5
=> X = 5 - 2Y .....................3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT EQN . 3 IN EQN. 2
=> 3 ( 5 - 2Y ) + 2Y = 3
=> 15 - 6Y + 2Y = 3
=> -4Y = 3 - 15
=> -4Y = -12
=> Y = -12 / -4
=> Y = 3
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
PUT Y = 3 IN EQN . 1
=> X + 2Y = 5
=> X + 2*3 = 5
=> X + 6 = 5
=> X = 5-6
=> X = -1
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
HOPE IT WILL HELP U.....
THANKS AGAIN.......
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
Similar questions