Question

Solve x+3/3 -x-3/2 = 1 Hence find p if 1/x + p=1 solve please​

Answer 1

$\frac{x + 3}{3} - \frac{x - 3}{2} = 1 \\ \\ \frac{2x + 6 - (3x - 9)}{6} = 1 \\ \\ \frac{2x + 6 - 3x + 9}{6} = 1 \\ \\ \frac{15 - x}{6} = 1 \\ \\ 15 - x = 6 \\ x = 15 - 6 \\ x = 9$

$\frac{1}{x} + p = 1 \\ \\ \frac{1}{9} + p = 1 \\ \\ p = 1 - \frac{1}{9} \\ \\ p = \frac{9 - 1}{9} \\ \\ p = \frac{8}{9}$