Solve (x+3a)(x+2b) =6ab
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Given question is (x + 3a)(x + 2b) = 6ab
Solution:
(x + 3a)(x + 2b) = 6ab
x (x + 2b) +3a (x + 2b) = 6ab
x² + 2bx + 3ax + 6ab = 6ab
Simplifying "6ab" on both sides, get:
x² + 2bx + 3ax = 0
Taking "x" common, we get:
x (x + 2b + 3a) = 0
Ether, x = 0 or x + 2b + 3a = 0
x = 0 or x = - 3a - 2b
x = 0 or x = - (3a + 2b)
These are the two solutions of the given equation.
Solution:
(x + 3a)(x + 2b) = 6ab
x (x + 2b) +3a (x + 2b) = 6ab
x² + 2bx + 3ax + 6ab = 6ab
Simplifying "6ab" on both sides, get:
x² + 2bx + 3ax = 0
Taking "x" common, we get:
x (x + 2b + 3a) = 0
Ether, x = 0 or x + 2b + 3a = 0
x = 0 or x = - 3a - 2b
x = 0 or x = - (3a + 2b)
These are the two solutions of the given equation.
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