solve (x+3a) (x+2b)=6ab
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Answered by
1
( x + 3a ) ( x + 2b ) = 6 ab
=> x( x + 2b ) + 3a( x + 2b ) = 6ab
=> x( x ) + x( 2b ) + 3a( x ) + 3a( 2b ) = 6ab
=> x² + 2bx + 3ax + 6ab = 6ab
=> x² + 2bx + 3ax = 6ab - 6ab
=> x( x + 2b + 3a ) = 0
Hence,
x = 0
Or, x + 2b + 3a = 0
Or, x = - 2b - 3a
=> x( x + 2b ) + 3a( x + 2b ) = 6ab
=> x( x ) + x( 2b ) + 3a( x ) + 3a( 2b ) = 6ab
=> x² + 2bx + 3ax + 6ab = 6ab
=> x² + 2bx + 3ax = 6ab - 6ab
=> x( x + 2b + 3a ) = 0
Hence,
x = 0
Or, x + 2b + 3a = 0
Or, x = - 2b - 3a
Answered by
3
❤❤Here is your answer ✌ ✌
( x + 3a ) ( x + 2b ) = 6 ab
=> x( x + 2b ) + 3a( x + 2b ) = 6ab
=> x( x ) + x( 2b ) + 3a( x ) + 3a( 2b ) = 6ab
=> x² + 2bx + 3ax + 6ab = 6ab
=> x² + 2bx + 3ax = 6ab - 6ab
=> x( x + 2b + 3a ) = 0
by zero productrule
Hence,
x = 0
Or, x + 2b + 3a = 0
Or, x = - 2b - 3a
( x + 3a ) ( x + 2b ) = 6 ab
=> x( x + 2b ) + 3a( x + 2b ) = 6ab
=> x( x ) + x( 2b ) + 3a( x ) + 3a( 2b ) = 6ab
=> x² + 2bx + 3ax + 6ab = 6ab
=> x² + 2bx + 3ax = 6ab - 6ab
=> x( x + 2b + 3a ) = 0
by zero productrule
Hence,
x = 0
Or, x + 2b + 3a = 0
Or, x = - 2b - 3a
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