Question

Solve x-5=3 by Trial and Error method.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer :-

• By trial and error method, the value of x is 8.

Given :-

• x - 5 = 3.

To find :-

• The solution of this equation by trial and error method.

Step-by-step explanation :-

• We are asked to find the value of x by trial and error method, so we will try all the values one by one (starting from 1)

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Trying with 1 :-

RHS

$\sf x - 5$

Substituting 1 in the place of x,

$\sf 1 - 5$

Subtracting 5 from 1,

$\sf -4$

RHS

$\sf 3$

LHS ≠ RHS

Therefore, 1 is not the solution of the given equation.

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Trying with 2 :-

LHS

$\sf x - 5$

Substituting 2 in the place of x,

$\sf 2 - 5$

Subtracting 5 from 2,

$\sf -3$

RHS

$\sf 3$

LHS ≠ RHS

Therefore, 2 is not the solution of the given equation.

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Trying with 3 :-

LHS

$\sf x - 5$

Substituting 3 in the place of x,

$\sf 3 - 5$

Subtracting 5 from 3,

$\sf -2$

RHS

$\sf 3$

LHS ≠ RHS

Therefore, 3 is not the solution of the given equation.

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Trying with 4 :-

LHS

$\sf x - 5$

Substituting 4 in the place of x,

$\sf 4 - 5$

Subtracting 5 from 4,

$\sf -1$

RHS

$\sf 3$

LHS ≠ RHS

Therefore, 4 is not the solution of the given equation.

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Trying with 5 :-

LHS

$\sf x - 5$

Substituting 5 in the place of x,

$\sf 5 - 5$

Subtracting 5 from 5,

$\sf 0$

RHS

$\sf 3$

LHS ≠ RHS

Therefore, 5 is not the solution of the given equation.

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Trying with 6 :-

LHS

$\sf x - 5$

Substituting 6 in the place of x,

$\sf 6 - 5$

Subtracting 5 from 6,

$\sf 1$

RHS

$\sf 3$

LHS ≠ RHS

Therefore, 6 is not the solution of the given equation.

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Trying with 7 :-

LHS

$\sf x - 5$

Substituting 7 in the place of x,

$\sf 7 - 5$

Subtracting 5 from 7,

$\sf 2$

RHS

$\sf 3$

LHS ≠ RHS

Therefore, 7 is not the solution of the given equation.

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Trying with 8 :-

LHS

$\sf x - 5$

Substituting 8 in the place of x,

$\sf 8 - 5$

Subtracting 5 from 8,

$\sf 3$

RHS

$\sf 3$

LHS = RHS

• Therefore, 8 is the solution of the given equation.

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