Question

solve : (x-5) (x-7) (x+6) (x+4) =504​

Answer 1

Please mark it the brainliest answer.

Answer 2

$(x - 5)(x - 7)(x + 6)(x + 4) = 504$

$( {x}^{2} + ( - 5 + ( - 7))x + ( - 5)( - 7))(x + 6)(x + 4) = 504$

$( {x}^{2} - 12x + 35)( {x}^{2} + 10x + 24 )= 504$

${x}^{2} ( {x}^{2} + 10x + 24) - \\ 12x( {x}^{2} + 10x + 24) - \\ 35( {x}^{2} + 10x + 24) = 504$

${x}^{4} + 10 {x}^{3} + 24 {x}^{2} - 12 {x}^{3} - 120 {x}^{2} - 288x + 35 {x}^{2} + 350x + 840 = 504$

${x}^{4} - 2 {x}^{3} - 61 {x}^{2} + 62x + 840 - 504 = 0$

${x}^{4} - 2 {x}^{3} - 61 {x}^{2} + 62x + 336 = 0$

${x}^{4} + 2 {x}^{3} - 4 {x}^{3} - 8 {x}^{2} - 53 {x}^{2} - 106x + 168x + 336 = 0$

${x}^{3} (x + 2) - 4 {x}^{2} (x + 2) - 53x(x + 2) + 168(x + 2) = 0$

$(x + 2)( {x}^{3} - 4 {x}^{2} - 53x + 168) = 0$

$(x + 2)( {x}^{3} - 3 {x}^{2} - {x}^{2} + 3x - 56x + 168) = 0$

$(x + 2)( {x}^{2} (x - 3) - x(x - 3) - 56(x - 3)) = 0$

$(x + 2)(x - 3)( {x}^{2} - x - 56) = 0$

$(x + 2)(x - 3)( {x}^{2} + 7x - 8x - 56) = 0$

$(x + 2)(x - 3)(x(x + 7) - 8(x + 7)) = 0$

$(x + 2)(x - 3)(x + 7)(x - 8) = 0$

$x + 2 = 0$

$x - 3 = 0$

$x + 7 = 0$

$x - 8 = 0$

$x = - 2$

$x = 3$

$x = - 7$

$x = 8$