Question

solve x square- 4 ax+4a square-b square=0 by factorisation method
Plz fast​

Answer 1

Answer:

${x}^{2} - 4ax + 4 {a}^{2} - {b}^{2} = 0 \\ {(x)}^{2} - 2(x)(2a) + {(2a)}^{2} - {b}^{2} = 0 \\ {(x - 2a)}^{2} - {b}^{2} = 0 \\ (x - 2a - b)(x - 2a + b) = 0 \\ x - 2a - b = 0 \: \: \: \: \: \: x - 2a + b = 0 \\ x = 2a + b \: \: \: \: \: \: \: \: \: x = 2a - b$